There is one thing naturally in favour of the lone trooper: Under no circumstances will the larger force take out more than a lone trooper.

If autoresolve corresponds somewhat to the visualisation, with units going against eachother individually (one squad on your side versus one squad on the other side), a single trooper versus 5 troopers with no other advantages or disadvantages has:

- A 50% risk of losing without causing any damage
- A 50% chance of taking out at least 1 unit
- A 25% chance of taking out at least 2 units
- A 1/8 chance of taking out at least 3 units
- A 1/16 chance of taking out at least 4 units
- A 1/32 chance of anihilating the enemy (without casualties)

Perfect casualty-distribution across 32 battles
x1: Army 5, Loner 0
x1: Army 4, Loner 1
x2: Army 3, Loner 1
x4: Army 2, Loner 1
x8: Army 1, Loner 1
x16: Army 0, Loner 1

Total loss over 32 battles:
Army 31, Loner 31

Given such a system, it seems that the effect should even out over time. For the sake of realism, the loner should be under fire more frequently than it should be able to fire when pitted against an army.

Given that units on the same side are not equal in purpose, cost or power, this is obviously a lot more complex, but I'd care to know whether or not the basic principle or the results are anything like what I describe. (Does 1 against 5 even units have a 1/6 win chance <16%>, a 1/32 (3%) win chance or something else; which is closer?)

If you're getting 16%-like numbers on that, isn't the autoresolver being awfully nice to the weaker side? (Getting to face your enemies 1 by 1, you'd have 50% five times, which is what I find to be slightly in excess of 3% chance overall. Having to face your enemies all at once should not be easier.)

Last edited by Sinister; 30/07/13 11:52 AM.