Originally Posted by Zaxtaj
Originally Posted by Tylm
sneak attack = normal attack + [ (0.5*level) rounded up ] D6
Ex : rogue lvl 5 (14 DEX) with dagger deals : 1D4 + 2 + 3D6


That is the way it should be handled, but it currently is not I checked when I was playing rogue during the alpha the litteral equation they were using to determine sneak attack damage is 1d6 * ((Level - 1)/2 + 1)
Additionally they are currently treating it as a second attack breaking the game in many aspects.

For example if at level 4 you take Warlock magic initiate for Hex and you will deal 1d6 on you normal hit, and an additonal 1d6 on the sneak hit.

This also applies to GWM +10 damage, if you sneak attack with a heavy weapon it will actually deal +20 damage.


Oh god...

((Level - 1)/2 + 1) is not rly bad, cause it avoids calculating the other rolls of the dice, and it allows to "smooth" the curve of the damage according to the levels.
DD5 : 1D6 -> 1D6 -> 2D6 -> 2D6 -> 3D6 ...
BG3 : 1D6 *1 -> 1D6 * 1.5 -> 1D6 * 2 -> 1D6 * 2.5 -> 1D6 * 3 ...
On the other hand we lose a lot of rolls, and therefore it increases the "random" effect frown

edit : Ok so that's EXACTLY what the op explained ... I'm so sorry !!!

Last edited by Tylm; 14/10/20 11:28 PM.