Larian Studios Forums Baldur's Gate III Baldur's Gate III - General The Rogue - Maths are WRONG

Assuming your character is 4th level, you should have 2d6 sneak attack damage, added on top of your regular damage 1d6 damage roll. It should look like (1d6+4)+(2d6). Generally the number of sneak attack dice you get is level/2 rounded UP.

So when I look at what they're trying to do.

Roll result 4(1d6)*((4-1)/2+1)=8

I read it like this.
They rolled a 4 on the weapons 1d6. They're then going to use that same result on all the subsequent sneak attack dice
So if we look at the first part, they rolled a 4 on their weapon damage.

The next set is trying to calculate the number of sneak attack dice.
(4-1)=3
3/2=1.5
1.5+1=2.5
They have to have rounded the result from 2.5 to 2, in order for the result to be 8.


Now wait.
If you're level 4, you should have 2 sneak attack dice, right? (The above formula also works for higher levels. 9 results in 5d6)
1(d6)+2(d6), and d6=4, the result should be 12, not 8.

So the mathematical error I'm seeing is...they subtract 1, divide, then add the 1 back.

If this is supposed to roll 1 dice, and then multiply by the total number of dice, then they should be adding only 1.

Roll result 4.
4*((4/2)+1)=12

Even then, that's actually not correct because we should be adding our dex modifier to our regular damage.
So it should be
4*((4/2)+1)+4=16



----EDIT----

New info
So, I just pulled up the game, and had Astarion sneak attack someone.
I saw two entries for damage.
1 Weapon damage. (1d6+DEX MOD)
and
Sneak Attack damage

Since they aren't actually combining all the damage from regular attack & sneak attack, the math checks out.
I rolled a 1 on my weapon damage, +2 for 3 damage.
And my sneak attack rolled a 4, so I did 4 damage.