No idea what the calculation gibberish is there for, but if your dexterity is 18 and the number rolled on 1D6 is 4 then 8 is the correct damage.
Hi Dwig, no need to understand if it's too hard for you. Just open a browser on google and paste the operation from the screenshot showing the damage:
4 * ((4 - 1)/2 + 1)
See the answer it returns, provide your observation. good luck.
I understood the numbers quite well (physics phd and all), what I do not understand is WHY they are being used. The 5E calculation for damage is weapon die + stat modifier for most hits (there SHOULD be no stat modifier on off hand hits, but BG3 does not follow this rule).
For a sneak attack there should simply be more dice. A level 4 rogue that hits with a valid sneak attack should roll 2D6 and add that to whatever the rest of their hit was. The equation appears to be a multiplier, but there are no multipliers like that in 5E that I am aware of. The hit was not critical, and even if it were the correct procedure would be to roll all damage dice twice (not apply some strange multiplier).
So the equation simply does not follow any rule for 5E that I am aware of.
As an aside regarding round off conventions... it is not all that uncommon to simply drop the fraction, depending on your goal. For instance, if you want to calculate the appropriate number of sneak attack dice then the equation (level -1)/2 + 1 will actually work, IF you drop fractions (this equation would then start at 1 die at level 1, and add a die on every subsequent odd level, which is exactly how it is supposed to work). In fact my best guess is that this is indeed what that equation means... but it is horribly formatted.
