I enjoy reading your inputs in this forum - oh, and your signature is priceless
I guess you are a rogue and this is a sneak attack.
Yes, I just edited my post to clearly state I was referring to the Rogue sneak attack calculation.
Sneak attack is 1d6 every odd level. Crit doubles the damage.
The formula should be ((level - 1) / 2 ) + 1 and its rounded down. This means its 1 for level 1 and 2, its 2 for level 3 and 4 and so on. This is the number of your sneak dice.
So sneak damage is only rolled once and its multiplied with the number of sneak dice.
Normally its 1d6 * number of sneak dice.
On a crit its 2d6 * number of sneak dice.
You made a mistake in the above. "((level - 1) / 2 ) + 1". The expression is read like this: "((level - 1) / 2 + 1)". Look at my screenshot. The location of the closing parenthesis is at the end.
So ((4 (level) - 1) / 2 + 1) = 2.5
Where we can precisely argue is with 2.5 can not be rounded (up or down) YET
. That's because the operation is not complete.
The operation is 11 * ((4 (level) - 1) / 2 + 1)
, once you complete it, then and only then you can round the number (up or down, doesn't matter, but technically it should be up - I have a research paper if you are interested
Try and paste "11 * ((4 (level) - 1) / 2 + 1)" in any compiler of your choice, you will always get 27.5, that of course you can round down if it matches D&D rules.