Just to finish off my point above, I just want to show how repeatable rolls in the world would look with different sized parties. You can graph this if you want.
Equation (1-(b^n))=y, where b is the chance of failure as a decimal, n is the number of party members, and y is the overall success rate. I'd recommend a 3D graphing calculator, like https://www.geogebra.org/3d?lang=en (try messing around with b, n, and y as the x, y, and z axes to make it work. Make sure your framing is set so that you can see the relevant section. It should produce a sort of lopsided wave tunnel. You can also multiply the whole left side of the equation by n to get a sense of the effect on combat. Again, try with different axes for different variables because geogebra isn't always cooperative. I'd do the math by hand but that sounds like work, and that's what I'm actively avoiding here.
ANYWAY, we can also just set the chance of failure as a set probability, like the worst-but-still-winnable case scenario of only one side wins, so 95% chance of failure. This gives us a 2d equation. You can use something like https://www.desmos.com/calculator for this. Equation is then 1-(0.95^x)=y. At this level, parties of the following sizes have the relevant chances of success at the "hardest winnable roll" in the game that can be repeated: Party of : Success Rate 1: 5% 2: 9.8% 3: 14.3% 4: 18.5% 5: 22.6% 6: 26.5% 7: 30.2% 8: 33.7%
I think the jump from having a less than 1 in 5 chance with a party of 4 to having a more than 1 in 4 chance with a party of 6 is pretty significant. Anyway, I'm beating the drum on this not because it's important or new information but because I'm procrastinating on other stuff.
Last edited by Zerubbabel; 30/01/2307:21 PM.
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